2y^2-3xy+x^2=16

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Solution for 2y^2-3xy+x^2=16 equation: 


Simplifying
2y2 + -3xy + x2 = 16

Reorder the terms:
-3xy + x2 + 2y2 = 16

Solving
-3xy + x2 + 2y2 = 16

Solving for variable 'x'.

Reorder the terms:
-16 + -3xy + x2 + 2y2 = 16 + -16

Combine like terms: 16 + -16 = 0
-16 + -3xy + x2 + 2y2 = 0

The solution to this equation could not be determined.

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